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SubjectFree lesson

Production of propagation of waves

ClassNotes Team 4 MIN READUPDATED 5 JUL 2026

Physics SSS2 Third Term

Sub Theme: Waves Motion without Material Transfer

WEEK 1

Production of propagation of waves

Performance Objectives

Students should be able to;

  1. Generate Mechanical waves.
  2. State the important characteristics of waves.
  3. Produce circular and plane waves using a ripple tank
  4. Generate and demonstrate longitudinal and transverse waves using suitable materials.

Wave

Content

A wave is a disturbance which travels through a medium and transfers energy from one point to another without causing any permanent displacement of the medium itself. If you drop a stone into water in a basin or swimming pool, ripples or waves will be seen spreading outward from the source of the disturbance. As the waves generated spread out, they transfer energy from one point to the other without the water moving in the direction of the ripples.

Production of propagation of waves

 

Production of propagation of waves

Waves can also be produced when one ties one end of a rope to a wall, hold the other end and make it to move up and down rapidly. Alternatively, get a long string and place both ends to two fixed points as shown below. Pluck the string i.e pull it either vertically downward or upward and release it. A wave will be generated.

Production of propagation of waves

 

Terms Used in Describing Waves

A wave can be represented as shown in the diagram below.

Production of propagation of waves

Terms as Applied to Wave Motion

Production of propagation of waves

1. Crest: This is a region of maximum upward displacement of the particles of the medium.

2. Trough: This is a region of maximum downward displacement of the particles of the medium

3. Phase: The particles of a wave are said to be in phase when they are at the same vertical distance from their mean position and are moving in the same direction.

4. Amplitude (a): It is the maximum displacement of the particles as measured from the mean position.

5. Period (T): This is the time taken by a particle to complete one circle or oscillation. Its unit is seconds. It can also be defined as the time taken for the wave to cover one wavelength. i.e from point P to Q or from Point O to R in the diagram above.

 

Production of propagation of waves

From a to B is a cycle. The time for the wave to move from A to B is called PERIOD

Period T = Production of propagation of waves

T = t/n

6. Frequency (f):  This is defined as  the number  of circles the wave makes in one second. It is measured in Hertz (Hz)

f = n/t

7. Wavelength (λ): This is the distance between two successive crests or troughs in phase. It can also be defined as the distance covered by the wave after completing a circle. It is measured in metres. In the diagram, the wavelength λ is the distance (P Q) or (O R).

8. Wave velocity (v): This is the distance () the wave travels with time (t).  its unit is m/s.

V = distance/time

During one cycle, the distance travelled = wavelength

Time to complete one cycle = period.

Therefore;

V = wavelength/period

V = λ/T

Since frequency is inverse of period, f = 1/T

V = λ/f

Example 1:

A wave travels a distance of 100m in 5 seconds. The distance between successive crests of the wave is 25cm. Calculate the frequency of the wave.

Solution:

Distance  = 100m,  time = 5 seconds   λ = 25cm = (25/100) = 0.25m

Velocity = distance/time

= 100/5 = 20m/s

V = fλ

f = v/λ

f = 20/0.25 = 80Hz

Example 2:

A radio station broadcasts at a frequency of 200 kHz. If the speed of the wave is 3.0 x 108 m/s, calculate the period and the wavelength of the wave.

Solution:

Frequency, f = 200kHz = 200000Hz,  velocity, v = 3.0 × 108 m/s

Period, T = 1/F = 1/200000

= 5 × 10−6seconds

V = fλ

Wavelength, λ =v/f

= Production of propagation of waves = 1.5 × 103m

Example 3:

A vibrating source which has a frequency of 500Hz produces a sound whose velocity in air is 330m/s. Determine the distance which the sound travels when the source completes 100 vibrations.

Solution:

f = n/t

500 = 100/t

t = 0.2sec

This is the time for the wave to complete 100 cycles.

V = d/t

330 = d/0.2

d = 66.0m

Alternative Solution:

Frequency f = 500Hz or 500 circles per second.

If the source makes 500 circles in a second, then it will take the source (100/500) seconds to make 100 circles  = 0.2s

Speed(v) = Production of propagation of waves

500 = 100/t

t = 0.2sec

Therefore s = vt = 330 × 0.2 = 66m